Question

Calculate the molality of 1 litre solution of 93 (weight / volume). the density of the solution is 1.84g/ml.

Answer 1

here is your answer hope it help

Answer 2

The question is incomplete, here is the complete question:

Calculate the molality of 1 litre NaOH solution of 93 (weight / volume). the density of the solution is 1.84 g/ml.

The molality of NaOH solution is 25.55 m

Explanation:

We are given:

93 % (m/v) solution

This means that 93 grams of solute is present in 100 mL of solution

Volume of solution = 1 L = 1000 mL

Mass of NaOH = $\frac{93}{100}\times 1000=930g$

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.84 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

$1.84g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.84g/mL\times 1000mL)=1840g$

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (NaOH) = 930 g

$M_{solute}$ = Molar mass of solute (NaOH) = 40 g/mol

$W_{solvent}$ = Mass of solvent = [1840 - 930] g = 910 g

Putting values in above equation, we get:

$\text{Molality of NaOH}=\frac{930\times 1000}{40\times 910}\\\\\text{Molality of NaOH solution}=25.55m$

Learn more about molality of solution:

https://brainly.in/question/8826560

https://brainly.in/question/12132057

#learnwithbrainly