Question

Calculate the molality of 10g of glucose c6h12012 in 90grams of water

Answer 1

Answer:

Explanation:

molality=w/gmw×1000/V

M=10/276×1000/90

M=10/276×100/9

That's all my frnd .now solve it u will get molality. Hope u will understand.

Answer 2

Explanation:

Formula of glucose is C6H12O6

Molar mass of glucose(M'')= (12 *6 ) + (1*12) + (16×6) = 180 g

Amount of glucose present(w1)=10 g

Amount of water present(w2) = 90 g

Molality = (w1 * 1000) / (w2 * M'')

=(10*1000)/(90*180)

=0.6173 m (ans)