Question

Calculate the molality of 13g benzene in 17 g ccl4

Answer 1

Answer:

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Explanation:

First: definition of molality:

molality = mol of solute per kg of solvent

Molar mass C6H6 = 78.11g/mol

13.0g C6H6 = 13.0/78.11 = 0.1664 mol

This is dissolved in 17.0g CCl4

Mol dissolved in 1kg CCl4 = 0.1664*1000/17 = 9.79 mol C6H6 dissolved in 1.0kg of CCl4

Molality = 9.79m.

Answer 2

Answer:

molality = moles/ wt of solvent

molality= wt of substance / GMW x 1000/ wt of solvent

m=13/78 x 1000/17

=1000/102=9.802 m