Question

calculate the molality of 15.00 M HCL with a density of 1.0 745 gram per centimetre cube ​

Answer 1

Answer:

28.46 m

Explanation:

15M HCl

in 1L of solution 15 mol of HCl is present

convert g/cm³ to g/L

1g/cm³=1000g/L

1.0745g/cm³=1074.5g/L

volume of solution=1L

so m=d×v=1074.5×1=1074.5g of solution

15mol HCl so mass of HCl=molarmass×moles

=36.5×15=547.5g

so mass of solute =547.5g

mass if solvent=1074.5-547.5g=527g=527/1000kg

molality=moles of solute/mass of solvent in Kg

=15/527/1000=28.46m