Question

Calculate the molality of 15% of sulphuric acid in the solution

Answer 1

molality=Wb*1000÷Wb*100g
molecular weight of H2SO4=98g/mol
=15*10÷98
=1.53 molal

Answer 2

15%H2SO4 solution means a 100ml of solution​containing 15 grams of H2SO4.
Now, C=1000w/MV
=>C=1000×15/(100×98)=1.5306122 M
=>C=1.530622mol/L =1.530622×98 gram/L=150gram/L