Calculate the molality of 1m solution having density of 1.05
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MOlar mass of NaNO3 id 85. density of the solution is ... As we have given 1 M solution of NaNO3, it means 1 mole
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Answer:
Calculate the molality of 1m solution of NaCl having density of 1.05
Explanation:
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Molality = mole of Nacl/wt.of solvent in kg
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wt.of solvent = wt.of solution -wt of NaCl
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=1.05×1000-58.5
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=105.0-58.5 =1000g =1kg
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m =1/1 =1
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