Calculate the molality of 2.5g ethanoic acid dissolved in 75g of benzene and also calculate mole fraction of both
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Answer:
the molality is 0.55 mole/kg.
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Explanation:
The molar mass of ethanoic acid is 2(12)+2(16)+4(1)=60 g/mol. The mass of ethanoic acid is divided with molar mass of ethanoic acid to obtain number of moles of ethanoic acid.
Number of moles of ethanoic acid =2.5g60g/mol=0.04167mol
The mass of benzene is 75 grams or 751000=0.075 kg.
The molality of ethanoic acid in benzene is the ratio of the number of moles of ethanoic acid to the mass of benzene (in kg).
It is 0.04167mol0.075kg=0.556m
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