Chemistry, asked by abdu64, 1 year ago

calculate the molality of 2.5g of ethanoic acid (CH3COOH) in 75g of ethanoic acid.

Answers

Answered by maheshwaranlupp0yaxy

0

Answer:

The molality is 2.5/60 × 1/75 × 10^-3 = 0.56 m.

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