Question

Calculate the molality of 2.5g of ethanoic acid in 75g of benzene. By the formula w*1000/MW

Answer 1

Answer:

0.55 molal

Explanation:

Molality is given by no. Of moles of solute / per kg solvent

m = 2.5 × 1000 / 60 × 75 = 5 / 9 = 0.55molal

Answer 2

Answer:0.5 molal calculate the moles of ethanoic acid and put it in the formula of molality that is n *1000/ mass of the solvent in kg that is n*1000/M*1000 which is equal to moles of ethanoic acid / weight of solvent