calculate the molality of 2M solution of a solute whose molar weight is 64, if the density of the solution is 1.2g/ml
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Correct option is
C
2.22
1ml of solution contains 1⋅02gm.
1000 ml or 1 L of solution ⟶1⋅02×1000 gm
=1020gm
Number of moles =Molarity×V
=2×1=2moles
Weight of solute =Molecular weight×moles
=60×2=120gm
Weight of solvent =1020−120=900gm
Molality=Weight of solvent ( in Kg)Moles of solute
Molality=2×9001000
=2⋅22m
Option C is correct.
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