Question

calculate the molality of 3 molar solution of nacl whose density is 1.25 gm/ml​

Answer 1

Answer:

Explanation:

density=1.25

m=3 mol /lit

molar mass of nacl=58.5

weight=n* molecular weight

           =3*58.5

           =175.5g

mass=density*volume

              =1000*1.25

               =1250

mass of water in solution=1250-175.5

                                           =1074.5

molality=no.of moles/mass of solvent in kg

                  =3/1.07=2.8