Question

calculate the molality of 45 gm of HNO3 dissolved in 80 gm of h2o​

Answer 1

Answer:

Moles of HNO₃ = 45 g / (45 g/mol) =2.0160 H (2*1.008) + 15.9990 O (1*15.999)

mol

Weight of solvent = 750 g = 0.80kg

Molality = Moles of solute / Weight of Solvent in kg

= 2.5 mol / (0.80kg)

=3.125 ans