calculate the molality of 45 gm of HNO3 dissolved in 80 gm of h2o
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Answer:
Moles of HNO₃ = 45 g / (45 g/mol) =2.0160 H (2*1.008) + 15.9990 O (1*15.999)
mol
Weight of solvent = 750 g = 0.80kg
Molality = Moles of solute / Weight of Solvent in kg
= 2.5 mol / (0.80kg)
=3.125 ans
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