calculate the molality of a 7.55Kg sample of a solution of the solute CH2Cl2(molar mass=84.83g/mol)dissolved in the solvent acetone .if the sample contains 929 g methylene chloride.
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0
Answer:
6855.58
Explanation:
so it is a wrong anawer
Answered by
0
Answer:
1.65 m
Explanation:
mass solvent ---> 7550 g − 929 g = 6621 g = 6.621 kg
moles solute ---> 929 g/ 84.93 g/mol = 10.9384 mol
molality = 10.9384 mol / 6.621 kg = 1.65 m
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