calculate the molality of a solution containing 20.7 grams of potassium carbonate dissolved in 500ml of solution density of solution in 1g/ml
Answers
Answered by
1
Answer:
Mass of K
2
CO
3
=20.7g
Molar mass of K
2
CO
3
=138gmol
−1
Moles of K
2
CO
3
=
138gmol
−1
20.7g
=0.15mol
−1
Mass of solution =(500mL)×(1gmL
−1
)
=500 g
Amount of water = 500 - 20.7
= 479.3 g Molarity
=
Mass of solvent in gram
Moles of solute
×1000
=
479.3g
0.15mol
×1000gkg
−1
=0.313molkg
−1
or=0.313
Answered by
0
Step-by-step explanation:
Mass of K
2
CO
3
=20.7g
Molar mass of K
2
CO
3
=138gmol
−1
Moles of K
2
CO
3
=
138gmol
−1
20.7g
=0.15mol
−1
Mass of solution =(500mL)×(1gmL
−1
)
=500 g
Amount of water = 500 - 20.7
= 479.3 g Molarity
=
Mass of solvent in gram
Moles of solute
×1000
=
479.3g
0.15mol
×1000gkg
−1
=0.313molkg
−1
or=0.313
the answer is 0.013
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