Question

calculate the molality of a solution containing 20.7 grams of potassium carbonate dissolved in 500ml of solution density of solution in 1g/ml
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Answer 1

calculate the molality of a solution containing 20.7 grams of potassium carbonate dissolved in 500ml of solution density of solution in 1g/ml

Answer:-

Molality of the solution is 0.31 m

Explanation:-

→ Molar mass of K₂CO₃ = 138 g/mol

Firstly, let's calculate the number of moles of K₂CO₃ in the solution :-

= Given Mass/Molar mass

= 20.7/138

= 0.15 mole

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Mass of the solution :-

= Volume × density

= 500 × 1

= 500 g

Mass of solvent :-

= Mass of solution - Mass of solute

= (500g - 20.7) g

= 479.3 g

= 0.4793 kg

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Now, molality of the solution :-

= Moles of solute/Mass of solvent in kg

= 0.15/0.4793

= 0.31 m

Answer 2

Ans = 0.313

See explaination in attachement ...