Chemistry, asked by shrishtitomar6776, 6 months ago

Calculate the molality of a solution containing 5.3 g of anhydrous na2co3 in 200 g of water?

Answers

Answered by yusufcemaltarik

0

Answer:

0.25

Explanation:

5.3/106 = 0.05 mole Na2CO3

m= mole / kg solvent

m= 0.05 / 0.2

m= 0.25

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