Calculate the molality of a solution prepared from 29.22 grams of nacl in 2.00 kg of water
Answers
Answered by
9
Answer:
0.25
Explanation:
molality=no.of mole of solute÷mass of soluvent in kg
m=0.5mol.nacl÷2kgwater
Answered by
7
Explanation:
To find molecular mass
add both the together
molecular mass of Nacl 35.45
so
29.22+35.45=58.44g/mole
Molarity =moles÷kg of solvent
moles= mass÷ molecular mass
29.22 ÷58.44
=0.50g/moles
molarity= 0.50÷2.00
=0.25molal
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