Calculate the molality of.Aqueous."caco3" solution having mole.Fraction 0.4
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Answers. solute mol = 0.05(1) = 0.05. Similarly, solvent mol = 0.95(1) = 0.95. Molar mass of water is 18.02 gram per mol. Let's multiply the moles of solvent(water) by it's molar mass to convert moles to grams: = 17 g. Convert g to kg: = 0.017 kg. molality of the solution = molality = 2.94 m.
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