Calculate the molality of asolution in which 36g of urea is dissolved in450g of water
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As we know molality is defined as no of moles of solute in 1 kg of solvent. So it has SI unit as mol/kg. And it is denoted as letter ‘m’.
Here the solute is Glucose and we need to find its moles.
No. Of moles = given mass / molecular mass
Given mass is 36 grams. And molecular mass of the glucose is 180 grams(C6H12O6).
No. Of moles = 36/180 = 0.2 moles.
Here solvent is water and we can take 50 grams of water as 0.05kg of water to get SI Unit precisely.
Molality = no of moles / kg of solvent
= 0.2 / 0.05 (mol/kg)
=4 m.
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