Chemistry, asked by sunilrathore393, 11 months ago

Calculate the molality of kcl solution prepared by dissolving 7.45g of kcl to make 500ml of the solution.density of solution=1.2g/ml

Answers

Answered by akshitabhardwaj
32

Hence the molarity will be 0.16m

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Answered by BarrettArcher
25

Answer : The molality of KCl solution is 0.169 mole/Kg.

Solution : Given,

Mass of KCl = 7.45 g

Volume of solution = 500 ml

Density of solution = 1.2 g/ml

Molar mass of KCl = 74.5 g/mole

First we have to calculate the mass of solvent.

\text{ Density of solution}=\frac{\text{ Mass of solution}}{\text{ Volume of solution}}

Now put the values in this formula, we get

1.2g/ml=\frac{\text{ Mass of solution}}{500ml}

By rearranging the terms, we get

Mass of solution = 600 g

As we know,  Mass of solution = Mass of solute + Mass of solvent

Mass of solvent = 600 - 7.45 = 592.55 g

Now we have to calculate the molality of KCl solution.

Formula used :

Molality=\frac{\text{ Mass of solute}\times 1000}{\text{ Molar mass of solute}\times \text{ Mass of solvent in Kg}}

Now put all the given values in this formula, we get

Molality=\frac{7.45g\times 1000}{74.5g/mole\times 592.55Kg}=0.169mole/Kg

Therefore, the molality of KCl solution is 0.169 mole/Kg.

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