Question

Calculate the molality of solution in which 0.63 gm oxalic acid dissolved in 750 gm of solution

Answer 1

Answer:-

• Mass of Solute=0.63g
• Weight of solvent=750g

Molecular mass of Oxalic Acid:-

$\\ \sf\longmapsto C_2H_2O_4$

$\\ \sf\longmapsto 2(12u)+2(1u)+4(16u)$

$\\ \sf\longmapsto 24u+2u+64u$

$\\ \sf\longmapsto 26u+64u$

$\\ \sf\longmapsto 90u$

Molality:-

We know that

$\boxed{\sf Molality=\dfrac{W_B}{M_B}\times\dfrac{1000}{W_A}}$

$\\ \sf\longmapsto Molality=\dfrac{\dfrac{0.6}{90}}{\dfrac{750}{1000}}$

$\\ \sf\longmapsto Molality=\dfrac{0.006}{0.75}$

$\\ \sf\longmapsto Molality=0.008m$