Question

calculate the molar composition of a mixture os so2 and so3 if its v.d is 36​

Answer 1

Answer:

Explanation:

Vapour density of SO2 is  =(32+ 2*16)/2  = 32

Vapour density of SO3 is  = (32 +3*16)/2 = 40

Say, SO2 is = x%

So, 32*x% + 40 * (100-x)% = 36

Calculate x = 50

So, SO2  = 50%

SO3 = 50%

Answer 2

Answer:

50% and 50%

Explanation:

Vapour density of SO2 is  =(32+ 2(16))/2  = 32

Vapour density of SO3 is  = (32 +3(16))/2 = 40

Say, SO2 is = x%

So, 32(x)% + 40 (100-x)% = 36

Calculate,

x = 50

So,

SO2  = 50%

SO3 = 50%

hope it helps