Question

Calculate the molar concentration of a solution containing 15.0 g of acetic acid (CH3COOH) and 200. mL of water.

Answer 1

Explanation:

This question is impossible to answer without further deatils . Especially what is the volume of the solution after adding 15.0 g CH3COOH to 20 mL water .

I will reword the question so that it is answerable:

What is the molar concentration of a solution containing 15.0 g of CH3COOH dissolved in water with a final solution volume of 20 mL ?

1.0 L = 1000 mL

Mass of CH3COOH dissolved in 1000 mL solution = 1000 mL / 20 mL * 15 g = 750 g

Molar mass CH3COOH = 60 g/mol

mol CH3COOH in 750 g = 750 g / 60 g/mol = 12.5 mol in 1.0 L solution

Molarity = 12.5 M