Question

Calculate the molar concentration of carbonic acid if 300ml of its solution contains 2.79 G of solute.Round the Answer to two decimal places. ​

Answer 1

Answer :-

Molar concentration of carbonic acid in the solution is 0.15 M .

Explanation :-

We have :-

→ Carbonic acid is solute .

→ Volume of solution = 300 mL = 0.3 L

→ Mass of solute = 2.79 g

______________________________

Molar mass of Carbonic acid [H₂CO₃] is :-

= 1 × 2 + 12 + 16 × 3

= 2 + 12 + 48

= 62 g/mol

Now, let's the numbers of moles of solute (H₂CO₃) present in the solution .

= Given Mass/Molar mass

= 2.79/62

= 279/6200

= 0.045 mole

Molar concentration :-

= Moles of solute/Liters of solution

= 0.045/0.3

= 45/300

= 0.15 M

Answer 2

Given :-

carbonic acid if 300ml of its solution contains 2.79 G of solute.

To Find :-

Calculate the molar concentration

Solution :-

Carbonic acid = H₂CO₃

Atomic no. of hydrogen = 1

Atomic no. of Carbon dioxide = 12

1 × 2 + 12 + 16 × 3

2 + 12 + 48

62 g/mol

No. of moles = Total mass/molar mass

No. of moles =  2.79/62

No. of moles =  279/6200

No. of moles =  0.045

Now

1 l = 1000 ml

300 ml = 300/1000 = 3/10 = 0.3 l

Molar concentration =  0.045/0.3

Molar concentration = 0.15 M