Question

Calculate the molar concentration of carbonic acid if 300ml of its solution contains 2.79 G of solute.Round the Answer to two decimal places.

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Answer 1

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• Answer :-

Molar concentration of carbonic acid in the solution is 0.15 M .

• Explanation :-

* We have :-

→ Carbonic acid is solute .

→ Volume of solution = 300 mL = 0.3 L

→ Mass of solute = 2.79 g

______________________________

Molar mass of Carbonic acid [H₂CO₃] is :-

= 1 × 2 + 12 + 16 × 3

= 2 + 12 + 48

= 62 g/mol

Now, let's the numbers of moles of solute (H₂CO₃) present in the solution .

= Given Mass/Molar mass

= 2.79/62

= 279/6200

= 0.045 mole

Molar concentration :-

= Moles of solute/Liters of solution

= 0.045/0.3

= 45/300

= 0.15 M

Answer 2

Answer:

Answer :

Molar concentration of carbonic acid in the solution is 0.15 M.

Explanation :

We have :

→ Carbonic acid is solute.

→ Volume of solution = 300 mL = 0.3 L

→ Mass of solute = 2.79 g

Molar mass of Carbonic acid [H₂CO3] is :

= 1 x 2 + 12 + 16 × 3

= 2 + 12 + 48

= 62 g/mol

Now, let's the numbers of moles of solute (H₂CO3) present in the solution.

= Given Mass/Molar mass

= 2.79/62

= 279/6200

= 0.045 mole

Molar concentration :

= Moles of solute/Liters of solution

= 0.045/0.3

= 45/300

= 0.15 M

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Step-by-step explanation:

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