Question

calculate the molar concentration of HNO3 (63.0g/mol) in a solution that has specific gravity of 1.42 & is 70. 5%(w/w)

Please answer in detail ​

Answer 1

molar mass of nitric acid (HNO3)

=1.42kg/L×10³g/Kg × 70.5g/100g

=1001.1 g/L

CHNO3=1001.1× (1 mol /63.0 g)

   =1001.1×0.0158

   =15.8 mol/L

i.e. 16 mol/L

Answer 2

As we know that;

specific gravity of  a solution is 1.42 & is 70. 5%(w/w)

So find out the molar concentration of HNO3 (63.0g/mol)

=1.42kg/L×10³g/Kg × 70.5g/100g

=1001.1 g/L

CHNO3=1001.1× (1 mol /63.0 g)

  =1001.1×0.0158

  =15.8 mol/L

Hence  the molar concentration of HNO3 (63.0g/mol) in a solution are 15.8 mol/L, i.e. 16 mol/L.