Calculate the molar concentration of O2 in water at 25°c under atmospheric condition where the partial pressure of O2 is 0.22 atm .the Henry's law constant for O2 is 1.3×10^-3 mol/L.atm
Answers
Answered by
0
Explanation:
According to Henry's law, P=K
H
×x
∴x
O
2
=
K
H
P
O
2
=
4.34×10
4
0.2
=4.6×10
−6
Moles of water=
18
1000
=55.5mol
∴x
O
2
=
n
H
2
O
+n
O
2
n
O
2
≈
n
H
2
O
n
O
2
⇒n
O
2
=4.6×10
−6
×55.5=2.55×10
−4
mole
∴ Molarity = 2.55×10
−4
M
Similar questions