Question

Calculate the molar concentration of Urea solution if it exerts and Osmotic pressure of 2.45 atm at 300 Kelvin.

Answer 1

hey here is ur answer....

$\pi = nrt \div v$
here pi=osmotic pressure =2.45 atm

T=300 K
R= gas constant = 0.0821

so n/V is molar concentration that is ..
$n \div v = \pi \div rt \\ molar \: concentration = 2.45 \div (300 \times 0.0821) \\ \: \: \: \: \: \: \: \: \: \: \: \: = 2.45 \div 24.63 \\ \: \: \: \: \: \: \: \: \: = 0.099 \: mol \: litre ^{ - 1}$

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