Question

Calculate the molar conductivity of 1M solution of sulphurics acid if its conductivity is 26x10*-2 Scm*-1.

Answer 1

Normality=nf×Molarity

                     =2×1=2N

Now,

λeq=1000×Nk

⇒λeq=21000×26×10−2=1.3×102Scm2eq.−1

I hope you can understand this