Question

Calculate the molar conductivity of a solution of MgCl, at infinite dilution given that the
molar ionic conductivities of 2° (Mg*2) = 106.15 cm’mor' and 2° (CI) = 76.35cm'mol
[Ans : 258.7 S cm’mol']​

Answer 1

Answer:

Mg Cl2 will break into one mg 2+ion and 2cl - ions.

Molar conductivity = 106.15+2*76.35

=258.75

Explanation:

According to kohlrausch law, at infinite dilution molar conductivity is the sum of the individual ions