Calculate the molar mass of Iron (II) Sulphate. [Fe = 56 u, S = 32 u, 0 = 16 u
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1
Answer:
Molecular weight of FeS
2
=56+2(32)=120 g/mol.
One mole (120 g) of FeS
2
will contain 2×32=64 g of S
30 g of FeS
2
will contain
120
30
×64=16 g of S.
Hence, the mass of sulfur contained in 30 grams of pyrites is 16 g.
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Explanation:
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