Question

calculate the molar mass of mohr's salt (Fe=56,S=32N=14,H=1,O=16)
​

Answer 1

Answer:

• 392 g/moles the required molar mass .

Explanation:

According to the Question

we have to calculate the Molar mass of mohr's salt .

It is also called Ammonium Iron (II) Sulphate .

It is given that

→ Fe=56

→ S=32

→ N=14

→ H=1

→ O=16

As we know the chemical formula of mohr's salt .

• $\bf \: (NH_4)_2Fe(SO_4)_2.6H_2O$

⇢ 14×2 + 4×2 + 56 + 32 × 2 + 16×4 ×2 + 6 × 18

⇢ 28 + 8 + 56 + 64 + 128 + 108

⇢ 92 + 300

⇢ 392g/moles

• Hence, the molar mass of mohr's salt is 392 g/moles