Calculate the molar mass of non volatile solute 3g of which when added into 90g of water elevate the boiling point by 0.26K (given Kb for water is = 0.52 kmolal^-1).
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∆Tb=kb molality
molality=mass of solute/molar mass*1000/weight in grams of solvent
put values
mass of solute=3g
weight of solvent=90g
∆Tb=0.26k
put
hope so helpful..
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