Calculate the molar mass of the following:
1.) H2O
2.) CO2
3.) CH4
And
Calculate the mass percent of different elements present in sodium sulphate (Na2SO4)?
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1.) Molecular (molar) mass of H2O
=> 2(1.008)+16u
=>18.016u
2.) Molecular (molar) mass of CO2 :
=> 12.01u+2(16u)
=> 44.01 u
3.) Molecular ( molar) mass of CH4:
=>12.01u+4(1.008)u
=> 16.042u
And
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your answer ...
1. H2O = 2 + 16 = 18 u
2. CO2 = 12 + 32 = 44 u
3. CH4 = 12 + 4 = 16 u
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Molar mass of sodium sulphate is = (2 × 23) + (32) + 4 (16)
= 142 g
Mass percent = Mass of that element in the compound / Molar mass of compound x 100
Mass percent of sodium = 46\142 x100 = 32.4%
Mass percent of sulphur
= 32/142x100
=22.6%
Mass percent of oxygen
= 64/142x100
= 45%
HOPE THIS HELPS YOU !! ❤️❤️❤️
your answer ...
1. H2O = 2 + 16 = 18 u
2. CO2 = 12 + 32 = 44 u
3. CH4 = 12 + 4 = 16 u
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Molar mass of sodium sulphate is = (2 × 23) + (32) + 4 (16)
= 142 g
Mass percent = Mass of that element in the compound / Molar mass of compound x 100
Mass percent of sodium = 46\142 x100 = 32.4%
Mass percent of sulphur
= 32/142x100
=22.6%
Mass percent of oxygen
= 64/142x100
= 45%
HOPE THIS HELPS YOU !! ❤️❤️❤️
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