Calculate the molar mass of the following.
Barium chloride (Bacl2]
Sodium hydroxide (NaOH)
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Explanation:
Formula weight of BaCl2 = 137.3 + (2 × 35.45) = 208.2
Mass of 0.37 mol of BaCl2 = 0.37 × 208.2 = 77.034 = 77 g (2 significant figures)
Sodium hydroxide is NaOH . Thus, its molar mass involves: MNa=22.989 g/mol. MO=15.999 g/mol.
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