Chemistry, asked by majedkarzan17, 6 months ago

Calculate the molar solubility of Copper (II) sulfide (Ksp = 6 x 10^-37) in a
solution in which pH is held constant at:
a)2
b)9
Hydrogen sulfide (K1 = 9.6 x 10^-8 & K2 = 1.3 x 10^-14)
(Briefly discuss your results)​

Answers

Answered by 20100081130050
0

Answer:

23

9.6

OK ok9 9ow

Explanation:

make me branlet

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