Calculate the molar solubility of Copper (II) sulfide (Ksp = 6 x 10^-37) in a
solution in which pH is held constant at:
a)2
b)9
Hydrogen sulfide (K1 = 9.6 x 10^-8 & K2 = 1.3 x 10^-14)
(Briefly discuss your results)
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Given:
To find:
Molar solubility of
Explanation:
The reaction is give as:
Solubility product equilibrium constant expression is given by:
Let the equilibrium concentration of ions be x M
M
Therefore molar solubility of CuS M
a) At pH=2 ; which is acidic , the solubility of salt increases due to Le Chateleir principle.
b) At pH=9 ; which is basic, the solubility of salt decreases due to addition
of ions and Le Châtelier's Principle says that the position of equilibrium will move to the left.
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