Question

Calculate the molarities and normalities of the solutions obtained on mixing.

(i) 100 mL of 0.2 M H2SO4 with 50 mL of 0.1 M HCl. ​

Answer 1

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Normality of any acid or base will be equal to gram-equivalent desolve in given volume

N = gram-equivalent/ volume(lt.)

When two or more compounds or elements react together their

gram-equivalent will be equal in simple way, 10 gm-eq of an acid will react completely with 10 gm-eq of base,

In given problem,

gm-eq. of H2SO4 = N*V(lt.)

and N = n*M where, M = molarity and n = basicity or acidity of an acid or base.

gm-eq of H2SO4 = 100*2*0.2*0.001

=0.04gm-eq

gm-eq of NaOH = 100*0.2*1*0.001

=0.02

remaining gm-eq of H2SO4 = 0.04–0.02

0.02gm-eq

Now,

gm-eq. = N*V = 0.02

Total volume =200ml = 0.2 lt.

N*0.2 = 0.02 = 0.1N

Hope you find it helpful!!!