Question

Calculate the molarity&molality of 9.8(w/w) solution of sulphuric acid. Given the density of solution is 1.02g/mol.

Answer 1

Explanation:

Given, 9.8 gm H2SO4 is present in 100 mL solution. (9.8% H2SO4 solution W/Volume)

Moles of H2SO4=989.8=0.1

Molarity=V(litres)Molesofsolute=1000.1×1000=1 Molar

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