Question

calculate the molarity an mole fraction of the solute in the aqueous solution containing 23.4g of NaCl in 90g water​

Answer 1

Answer:

to find the the molarity an mole fraction of the solute in the aqueous solution containing 23.4g of NaCl in 90g water we use the following description

Explanation:

moles of solute = 23.4 / 58.5

        = 0.4 weight of solvent (water)

        = 0.09kg Molality (m)

             = no. of moles of solute / Weight of solvent in kg.

          = 0.4 / 0.09 = 4.4444 ~ 4.45

​total no.of moles in a solution = moles of water + moles of solute

   = 5 + 0.4 = 5.4 ​

Mole fraction of solute = no. of moles of solute / total no. of moles in a solution

= 0.4 / 5.4 = 0.740

Answer 2

Answer:

MOLALITY - 4.45

MOLE FRACTION - 0.074

Explanation:

moles of solute = 23.4 / 58.5

       = 0.4

weight of solvent (water)    = 0.09kg

Molality (m)   = no. of moles of solute / Weight of solvent in kg.

                       = 0.4 / 0.09

                       = 4.4444 ~ 4.45

​total no. of moles in a solution = moles of water + moles of solute

                                                    = 5 + 0.4 = 5.4 ​

Mole fraction of solute = no. of moles of solute / total no. of moles in a solution

                                        = 0.4 / 5.4 = 0.740

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