Calculate the molarity and normality k2co3 solution containing 2gram k2co3 in 250 ml solution
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Mass of K
2
CO
3
=20.7g
Molar mass of K
2
CO
3
=138gmol
−1
Moles of K
2
CO
3
=
138gmol
−1
20.7g
=0.15mol
−1
Mass of solution =(500mL)×(1gmL
−1
)
=500 g
Amount of water = 500 - 20.7
= 479.3 g Molarity
=
Mass of solvent in gram
Moles of solute
×1000
=
479.3g
0.15mol
×1000gkg
−1
=0.313molkg
−1
or=0.313
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