Question

calculate the molarity and normality of 0.74 gram of calcium hydroxide in 500 ml solution​

Answer 1

Answer:

Explanation:

I get extremely frustrated and disappointed when I see nonsense questions like this in a chemistry forum . Do the people who set these questions ( presumably “teachers” ) know what they are doing .

The situation is as follows:

Solubility of Ca(OH)2 at 20°C = 1.73 g/L

Molar mass Ca(OH)2 = 74.05g/mol

Therefore the maximum concentration of Ca(OH)2 solution that can be prepared at 20°C = 1.73g/L * 74.05g/mol = 0.023 mol /L

Therefore attempting to calculate the mass of Ca(OH)2 in a 0.5M solution is total nonsense. I suggest that you take this up with your teacher - you are entitled to some explanation.

Answer 2

Answer:

some time this happens.

Explanation:

answer is 0.023 g/ moles