Question

Calculate the molarity and normality of a solution containing 3.15 gram of hydrated oxalic acid dissolved in 250 ml of solution

Answer 1

The formulae of hydrated oxalic acid is :

H₂C₂O₄. 2H₂O

The molar mass of this compound is :

2 + 24 + 64 + 4 + 32 = 126

Moles = 3.15/126 = 0.025 moles

Molarity :

0.025 moles —> 250 cm³

? —> 1000cm³

1000/250 × 0.025 = 0.1 M

Normality = number of hydrogen ions × molarity

Normality = 0.1 × 1 = 0.1 N