Question

calculate the molarity and normality of a solution of oxalic acid containing 12.6 gram of the acid in 500 ml of the solution​

Answer 1

Explanation:

MM of oxalic acid =C2H2O4=90

MOLES =12.6/90=0.14

molarity=n/v(L)

=0.14*1000/400=0.35 Molar

normality= molarity×nfactor

=0.35×2

=0.7