Chemistry, asked by aggastia, 10 months ago

calculate the molarity and normality of a solution of oxalic acid containing 12.6 gram of the acid in 500 ml of the solution

Answers

Answered by halfbloodprinceabhi

3

Explanation:

MM of oxalic acid =C2H2O4=90

MOLES =12.6/90=0.14

molarity=n/v(L)

=0.14*1000/400=0.35 Molar

normality= molarity×nfactor

=0.35×2

=0.7

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