Calculate the molarity molality of a 13% solution (by weight) of sulphuric acid (density =1.020gcm¯³)
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13% weight of h2so4 solution means 13g of solute in 100g of solution
for water 1g=1ml
molarity =13÷98×1000÷100
molality =1000M÷1000d_M.molecular weight of solvent
here M= molarity
for water 1g=1ml
molarity =13÷98×1000÷100
molality =1000M÷1000d_M.molecular weight of solvent
here M= molarity
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