Question

Calculate the molarity of 10.6 percent w/v sodium carbonate solution

Answer 1

Answer:

Molarity can be found with this formula: molarity=number of moles/volume (L) We know the volume, which is. 500mL = 0.5 L. ...

We have 10.6g/106g/mol = 0.1mol. From n = MV, 0.1 = M x 0.5, so M = 0.1/0.5 = 0.2. The solution is 0.2M. 1.4K views. ...

(10.6 x 1000)/(106 x 500) =0.2 M. 468 views.

Answer 2

Answer:

Molarity of solution is 1M

Explanation:

Given,

The weight per volume(w/v%) of Sodium Carbonate=10.6%

It means that there is 10.6gm of sodium carbonate present in 100ml of water

The Molecular weight of Sodium Carbonate is 106g/mol

Now we can find no.of moles using these known values

$n = \frac{wt.of \: Na_{2}C0_{3}}{molecular \: wt.of \: Na_{2}C0_{3}}$

hence

$n = \frac{10.6}{106} = 0.1mol$

Since,no.of moles and volume are known,molarity can be found by using following relation

$molarity = \frac{n}{volume(in \: ml)} \times 1000$

substituting known values,we get

$molarity = \frac{0.1}{100} \times 1000 = 1M$

Therefore,Molarity of solution is 1M

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