Question

Calculate the molarity of 10 g sodium carbonate dissolved in 500cm cube of water​

Answer 1

Answer:

0.5 molL^-1

Explanation:

Molarity =

$\frac{n \times 1000}{v \: ml}$

Molar mass of NaOH = 40gm/mol

No. of moles of NaOH =

$\frac{10}{40} = 0.25mol$

Therefore, molarity =

$\frac{0.25 \times 1000}{500} = \frac{250}{500} = 0.5mol^{ - 1}$

Answer 2

Answer:

answer :0.235m or 0. 2L=236mol

Explanation:

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