calculate the molarity of 2.5 molal urea if it's density is 1.20 gm/ml
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2.0 m
1.2 m
1.0 m
0.6 m
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Solution :
2 M solution has 2 moles of solute dissolved in one litre (1000 mL) of the solution
Mass of the solution =V×d=1000mL×1.2g mL−1=1200g
Mass of solvent =(1200−200)g=1000g=1kg
Molality of solution (m) =No. of moles of soluteMass of solvent in Kg
2 mol1 kg=2mol Kg−1=2m.
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