calculate the molarity of 20% aq. NaOH solution having density of 0.80 g ml^-1
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Sol.
Volume of 100 g of solution = ml\ M = or d = = 1.249 » 1.25
Ex.2 The density of a solution containing 13% by mass of sulphuric acid is 1.09 g/mL. Calculate the molarity and normality of the solution-(A) 1.445 M (B) 14.45 M (C) 144.5 M (D) 0.1445 M
(Ans. A)Sol.
Volume of 100 gram of the solution = = mL = litre= litreNumber of moles of HSO in 100 gram of the solution = Molarity = = ×
= 1.445 M
Ex.3 Calculate the molarity of pure water (d = 1g/L)(A) 555 M (B) 5.55 M (C) 55.5 M (D) None(Ans. C)
Sol.
Consider 1000 mL of water Mass of 1000 mL of water = 1000 × 1 = 1000 gramNumber of moles of water = = 55.5Molarity = =
= 55.5 M
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Volume of 100 g of solution = ml\ M = or d = = 1.249 » 1.25
Ex.2 The density of a solution containing 13% by mass of sulphuric acid is 1.09 g/mL. Calculate the molarity and normality of the solution-(A) 1.445 M (B) 14.45 M (C) 144.5 M (D) 0.1445 M
(Ans. A)Sol.
Volume of 100 gram of the solution = = mL = litre= litreNumber of moles of HSO in 100 gram of the solution = Molarity = = ×
= 1.445 M
Ex.3 Calculate the molarity of pure water (d = 1g/L)(A) 555 M (B) 5.55 M (C) 55.5 M (D) None(Ans. C)
Sol.
Consider 1000 mL of water Mass of 1000 mL of water = 1000 × 1 = 1000 gramNumber of moles of water = = 55.5Molarity = =
= 55.5 M
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