Calculate the molarity of 250mL solution containing 53g of Na2CO3?
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volume=250ml
mass=53g
molecular wt(NA2CO3)=2×23+12+3×32=46+12+96=154
molarity=mass/mol.wt*1000/v in ml
=53/154×1000/250
=0.344*4
=1.376
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